0114 CS Henry

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Already what you might have forgotten about were things that you know we struggled with in the past. And as usual, we can do 30 minutes of that, just a bit of theory, and then 30 minutes of leak code. How does that sound? Yeah. Okay, so if I say what is a word? What's a word? Say malware. I mean, it's not malware, but it's. Propagates through the Internet. It's a piece of program. Yeah, that's the key points here. Gets. No, sorry. Sorry. Can you? You're almost there. That's why that's why I stop talking you. There's a key point to it. It's self replicating. Replicating. So that's obvious, right? But this will usually count for one points when they ask you, Oh, what's a worm? So just to keep that in mind, what's spwear? It accesses so malware that access is like your what you're doing on the screen, your interactions Oh wear to spy Yeah spy interactions interactions in the objective of like stealing past forthem to another Yeah. Your passwords or money. Yep, what's fishing? Fishing is setting up a fake website or a fake information gathering thing to get personal information. What's the difference between fishing? Yeah I got a personal info. So this will usually be like a text message or like one of these really corny like Oh, redeem your free gift card or something like that that you'll get like as a message. And what's the difference between fishing and farming? I forgot. Sorry, no worries. It's a bit nuanced here because they're kind of basically the same thing, both fishing and both forming. If you hear or start seeing a ph somewhere, it's a steel data. So I'm going to make a little grid fishing. Informing. The basic way to think about it is if you're fishing, you know you're not putting in much effort. No, you're you're just sending like spam like spam calls, emails and you can detect it via something like you know misspellings. Right or AI like you you can see like an m dash in there is probably not going to be a real email, right? Whereas in farming it's a bit more targeted. So it's it's targeted. So Yeah, let's say you want to hack into Google for some for whatever reason and you send, who's the secret CEO of Goole's? Tim Cook? I don't know if he's the CEO, but let's say I don't know, let's say you want to hack into SpaceX or or Tesla and you send an email to ion musk, right? And you're like, Oh, you know this email and you make it look legit, make it look like a company email. And then this the websites you might click on, right? You might have like a website and that website that they click on would be like a fake, right? And then theyclick on it, theyput their password, and then suddenly you've got Elon Musk's password for his bitcoin account and you're a very happy man, but you know not him, he said. So basically, it's kind of a more targeted way to steato steal money and information. Yeah. All what's a dos attack? It's when a computer sends corrupted or or information to try to overload a server yewhat they stand for. Denial of service, yes, was. How do you say the word again? Distributed denial of service. Yes, exactly. And what does that mean in practice? It's a malware that's sent to many computers to do a doos attack. Exactly. Very nice. They all, they all, at the same time, hit the same server. So it just goes down. Okidoki, all right. One of a bit of a boring one. What's an ide? Integrated development environment and what's the advantages of an ID. There's many built in adons functions to use. It provides a. Easier to set up the environment, easier to code. More efficient to code in and more efficient. Very nice. What about disadvantages? Any think you no, I mean. Like han Yeah there's not that many. The main one is that you know it's bulky and slow, which you don't really need that much setup for like a small project. Another one, 21, you can Yeah you can exactly can get a lightweight one. So that's why there's not that many disadvantages to it. But basically, Yeah if you have an ID, it just makes it easier. You know you can also have I'll just a few of them. You also have like debuggers where you'll have like interpreters that will like highlight code. So I don't know if you used an ide before, but you might create a new variable like x and then you never use x so it like there's a squivy line underneath it to tell you like, Hey, you haven't used this bar able here. So Yeah, there's a lot of things you can say but Yeah, just wanted to test you out on that very nice. What's inside of an ip packet? Or firstly, what's an ip packet? It's a packet of data sent over the Internet to a receiver and what's inside of it. There's the data, there's the ip of the sender and the receiver. Yes. Can you think of one more thing? Metadata yes, metadata. That's a good one. That's a good one for for metadata here inside of it, you might find something like ip number. So for example, ipv six or v four, v six slash v four, or you might also find like the the number. So ip number would be like, Oh, this is the fourth ip packet I've sent to you or something. What about tcp? What is that? It's a transmission protocol. You send a file with send an ip package with an acknowledgement, and you don't send another one until they send back an acknowledgement or if. Or if it's a runtime error or something that they have and you're just gonna resent the whole thing exactly red. So it's pretty much exactly what you said. You have just to to say what you what you said already. In other words, you have the sender, a receiver b and a sends a packet and b says, okay, I got it. And then once a set and boom, he sends a packet, b says, okay, I got it. Sends a packet, okay, I got it. And here it looks like it's cereal. What does cereal mean? Cereal like this. In order Yeah exactly so. No, nothing. Sorry. No, no worries. You question. But because I was gonna say you can you can do it serially, but you're not actually doing it. Seriyou can do it in parallel, right? You can send several packets before b confirms and then b can say yes to each of them individually. So you don't have to actually do it serially. You can just do it in parallel. Okay, very nice. What is all right, let's go to browsers. What is ssl? What does it stand for? What does it do? I don't know what about what it does. No, sorry, I don't know what if I say certificate? Is that right? Yeah, it gives you when you enter a website, it's gives you a certificate that did is the write websites and not a sort of hijacks website. Very nice. And how does the flow work? Like how how does it work if I go to a website right now or if you were to go to a website, how do you how does the flow work between you entering the website and then getting like a certificate, making sure it's the right one? You go in the website, you send it link or address of the website to the to. The server that has the certificates and it will check in its list if the certificate is of that link is there, if it's not at all sent back that it is not safe to enter that site. And then. Basically, you forgot one small thing about that. It gets to certificate through the site. So site sends back the certificate and this is called the certificate authority. So basically, you've basically got it. Just remember that ssl is called secure socket. Layer and it kind of this is the protocol, right? You send the link, the site replied for the certificate, you get the certificate, then you look in your own repository of certificate authorities, you're like, okay, I'm going to ask certificate authority if this is a good website, if I'm being, you know, if this is gonna to be dangerous for me getting on there and then you ask certificate authority and the registry will say either yes or no and then if it's a no, you'll actually get a page on a prome. You might have seen it before. It says this website isn't secure, right? And it looks like you can't enter a website, but all you have to do is Press advanced and then proceed anyway. So you can still go on those websites is just a way to protect users. Okay, very nice. And just to kind of complete this, the site here, I've actually done this myself. The sites here will basically, when they first create their website, theygo to the certificate authority and theysay, Hey, my name is, I don't know, John, right? My name is John, and I wanna set up a certificate for this website. And then what you'll do is you'll send the detail, you'll send your email address, you'll send your ip address and then the registry will say, okay, that's your that's your website and then itreply back with an, okay, and that's it. And then basically they will store your certificates and then now can you can access it safely and you need to renew this every month. But you don't know. It's not that important for you to know, but you do need to do this every month. Key, don't key, all right? Okay. You've had a few troubles with this one before. Okay, what do I have to do? All right, so please get out your pen and circle. Will me the primary storage types in this in this list of things you have to give me the permission to my bad. I'm just that's you right now. 一个。The primary storage types. Sorry, I forgot, primary is the one that. Is that keeps data within itself, even nothat runtime. You tell me I'm being cheeky. I'm sorry. Yeah, I'd rather not tell you and see if you remember or not. From httssd magnetape. Okay, so I see what you went for. Unfortunately it's not correct so I'm gonna regive you the definition. Primary storage is a type of storage that is directly accessible by the cpu during runtime. So okay, if youmind maybe I can help you deleting these and trying again. Oh it very nice. Okay, you've got it. And trying again and seeing if you can if that changes your answer. This is d and hhd are accessible, right? So almost you're halfway there. In fact, these are not directly accessible by the cpu. Actually. This is really, really interesting and I wish I could teach you about this, but it's just not in your curriculum. But the way we access httD and ssd is done by a separate component called a drive access or or something I forgot, but it uses a very cool algorithm. But yes, it's not for this kind of class, but you're you're basically there, right? These are secondary storage types. They're secondary because the cpu can still access them. Adjust would need to go through this whole like process, but it's not directly accessible by the set, by the cpu. However, this is good. This is good. This is good because basically the cpu ram is while it's not really there, usually this four level, so ram is a bit further away. Ram is considered to be directly accessible directly in memory because it's super easy to just go get computer can just go get it. And what's by the way, what's the difference between ram and ram? Read only and random random access. Yeah what does that mean in practice? You can only read from a ram, ram, which means it's pbuilt as a ram. You can store and read any data exactly. And now bonus question and see where is the heap in those? The ram, exactly. The heap is in the ram. Yes. Rom is just used for startup or like bios setup, things like that. And a key point is that it persists even if the computer switches off was as ram is no more electricity, no more storage, it just turns off. Great. Okay. Now would you mind removing the I don't know how you did that so quickly. You just select one. I see three, select tool and then you just select and remove. Nice. Nice. Okay. You're you're quicker than me. Okay. Now tertiary tertiary types, tertiary storage types. Would you mind circling the tertiary types? Ps, now there go. Yep, that's perfect. Secondary types. Okay, I'll remove those ones. The usb is also a secondary type. Usb is also Oh, that's a good question. Good question. Yes, wait, let me get your syllabus out, because they can can be tough. Most of these definitions are done by cie. So they're not like they're not global. But yes, hdd and ssd are indeed are indeed storage secondary storage types. Would you now please order one to the last number? So one being the fastest and then n being the slowest, order how fast each of these. And usb is a secondary storage device. Perfect. Yes. These two here. I would have forgiven you if you had said 23. As you know, they're they're quite similar in terms of access speed. So this is perfect wherever you see registry like ldr, R, cash, Yeah exactly. Cash, right. Registry will still be quicker than cash always. Why is that? Why is registry quicker than cash? Just closer to the cpu than even cash? Yeah, exactly. It's closer. And we already know what's inside the registry. We don't know what's inside the cash ache. You can have a cash mesthe, cash miss, right? If you try to get something from the cash ache and it's not there and you still need to find the item, you need to run a hashing algorithm, whereas a registry is just right there. So registry is always a fastest, very, very nice, okay, a big improvement from from last time we needed this question. So I'm quite confident that if you see this, you'll be you know you'll be feeling a lot more confident about this. Great. Any questions so far? No. All right, let's do maybe one more before we go to leap code. Do you if I were to say, if I were to ask you what is the Universal Serial Bus, what would you tell me? The data bus. What does it do? It connects, it allows transfer exchange of data within the cpu. Yes, exactly. And if I were to tell you, if I will, like if I have a 64 bit computer, right, 64 bit architecture computer, the wilength would be 128 bit for the bus. Yeah 64 bit then it's also 64 then exactly. Exactly. That's a that's a common a common gotcha. But if it's a 64 bit architecture, then 64 bit bus, otherwise it's 32 bit. Why does that matter whether it's 64 or 32 bit? It matter. Depenif you have a if you're on a 32 bit architecture and you have a long, long int ch, which is eight bytes, 64 bits, you're going to have to take two cpu calls or two clock cycles to even send that data. That's a perfect answer. That's a perfect answer. Not only that, but you're going to have an increased cash acsize, right? You're going to have an increased well ram access because you've got pointers. Your pointers will not be 64 bits long, which means you have not double, but two to the power of whatever. 32 will be six or five more. You can also have more ram and you can also have more Yeah, exactly. So you totally understand there. And so that's why it's so important. You can just access things right? You've got more heat, more memory. So 64 bit and 64 bit is kind of the limit. It's got 128I think for like supercomputers. But like if you're doing more than 64 bit, then you know maybe nasa is doing that, but not not many people are. That's the bus. Quickly before we go to lecode de, I'm just going to ask you to draw me a cpu architecture here. Detor, Yeah, there's. See you to the. There's an accumulator somewhere near it. There's ram above, but not needed. There's cash. This the. Hil, you? I think that's all you need for a basic cpu. There's some things that are right, there's some things that are missing. But globally, I can see you've got the idea here. Let's add a bit more to your cpu. So you said there's a Universal Serial Bus. What other types of buses are there? Maybe don't maybe bus. There's a bus for the ram. It's everything that connects. All of these are one. The webhas a separate bus. What's the bus that connects all of these from the cu? Data bus control bus control bus. In actuality, you have three different types of bus. You have the control bus. This one, you have the address and the ram. Yeah, exactly. Bus and you have the address. In reality, these two are kind of interchangeable, but they basically will ask you the three data buses, well, data address and control. Remember, for the cu, ram is gonna to be in the same category as ram. So you wanna move that out somewhere here, right? And have it like this. Just a conceptual thing when talking about how detailed we can make a cpu, there's actually quite a few ways to make a cpu. So I think next class, what I'll do is I'll bring a schematic, and we're just going to try and ingrain you know what what cpu it is. But rule of thumb is you've got the accumulator down, which is perfect. You've got the control unit down, which is absolutely critical. You've got the cache, which with A C or just cache like this, these are the three and and the althese are the main things. But there's also the memory data register, the mdr, the memory address register, the maand. Then you also have the pc, the program counter, the accumulator. Remember, it's just a register to store what happens inside of the alu nif. One more, you have the instruction register, the ir, right? And then your schematic here is kind of correct. Wehave to do it with a bit more detail here. But youhave like a little box around it. The alyou would be inside that box and then youhave like some kind of data and address bus with the ram, right? So youhave it youhave youhave basically a bus that connects all these things. This would be like the data bus plus address bus, right? That would be 64 bit. If it's like a if it's like a 64 bit computer and then each of these right would have like. Each of these would kind of connect to the cu in a certain way with an independent bus, which would be the control bus. And so Yeah, they would be on and off the bus. And there's like a coordination algorithm based on the pc, the program counter. And in reality, when I was learning how to build, you can build your own eight bit computer, but when I was learning how to do that, the program counter has like a big and gate with every single components in the computer to be like you can run or you can't run because it's to do with the way the electricity moves through the exactly the clock. Okay, I'll I'll stop planning ding, let's let's let you share your screen. There we go. Already on leak code. I don't see the little star for the favorite on the top right now. I'm joking. Let's do. I don't know. I'm joking. I'm joking. I'm joking. Let's let's go for an easy one. Warm up slow. But I think we're getting ready to do our first hard one, a first medium one. But let's let's do a medium. So if you actually scroll up, there's a way we can filter these. If you go to on the left there you've got like a filter icon. And here you can say difficulty is easy. Very nice and Yeah, let's have a look. Okay, okay, and scroll down. Go climbing stairs. I think we did that one together. Yeah, we just did that one. Yeah. What else? What else about battree? Maximum depth battree tree? Oh, this one, 121. Best time to buy and sell a stock. It's a good one. Okay. Do you see what a stock is? Yeah, cool. Okay. Then I won't give you too much detail. I'll let you read it. And then once you've once you've read it, let me know what you think. And and I can kind of give you some more context if you need it. But if you feel confident and you can just kind of start going at it. Okay, I'm thinking you just propagate through the you just find the max, get them in and then find the max. Okay, what about though? If you have a situation like this, imagine this is your stock, imagine it's going like this and then it goes up like and then it goes like this. Would your algorithm still work if the stock was like this? Mean you would find the two differences. So youfind, this one would be the one here and here, and this would be the min, and this would be the maximum, right? Yeah. I mean, it would propagate through and find them in. I see, I see. So basically, okay, okay, wait. So youbasically do youonly find the youonly find the max after the mid right is what you mean. Yeah but if you have these, I think I could add just get the first one and then get the second one, calculate the profit and then continue on calculating. If that second one is lower than the first, I would change the variable to store the second one. Very, very nice. Very, very nice. Okay, I'll let you I'll let you write some code. Is there any limit on the size of a like the size of the price? I think you might nah, I don't think there's a limit. Maybe it takes the crassive. Go on. I try, then. Wait that wait that size. I'm going to get myself a glass of water, but you seem to be on the right direction, so I'm just going to let leave you code. I'll be right back. Nice. Oh, wait, I muted you tonight. I did not mute myself okay okay. Very nice. I think you've got it, but there's something missing here. Yeah, I have to calculate the remaining thing, but. Is that it? Almost there. Give it a run, though maybe I'm wrong, think it sort way and I need to lock in again. Okay, so close what happened here? So before we keep going, before we keep coding, try to explain to me in your words, what your strategy is to try and find the maximum profit. I'm going to first find the first minimum and then if I it is that minimum, then on the next try, it would try to find the difference. So basically what you're doing, let's say you've got a stock like this, I wait, I need a last profit or something. I think I need a last profit to restore it. And in comparison. Then I need to initialize this. Yeah, it works. You got it. Hey, let's go. Very nice. Let's see. So. Close. But what happened there? It seems so let's let's have a look at. At. What could happen here? If I look at your code, last profits for entire in size if min prices. So if you find a min that's less, then for example, zero here, we don't actually initialize last profit. So it could be any number. But let's say it's a very large number, then what we do initialize, where do you initialize here? Prices is Oh, you're right. So last last price is equals profit. So if min prices is less than min, so basically you just keep going down, right? So let's say you've got let's say you've got a graph line that looks like this, right? Keeps going down. So you keep going down. And so you reach a minimum here. Then if you found your minimum, then you just last profit. That's profit. Profit versus profit, when it's mint, you start going up. But once you start going up, you say profit equals here and you just say, profequals presses I minus min. Yeah. So because it doesn't change. Yeah. Yeah, exactly. And the profit will just be this change here. But here then you say if last profit is greater than profit, then profit equals last profit. But then here you so it's quite close. But you say price last profit equals profit, which you're just saying, Oh, it's the current profit now and then you're reassigning profit to be pressed I management as so you're only going to ever have that maximum difference there if that makes sense. And I just want to before we keep going, did that make sense? What I said? Yeah, Yeah. Okay. And the problem with that is that you'll never find the the change in price. So I want to propose something a bit different because you're you're halfway there. Well, you're 90% of the way there really. But think about think about this again from a more like abstract perspective. So if you go back to the description of the problem on the left hand side on the problem list, and I think I know like what mistake I made, it's if there's like a. One, 27. And then there's a three end like. 15, I just do wait. We know that still counts, right? No one, 27 is run. Let's see if men is good. Purses continue. I think this should work, though I don't know why. Good. Last profit it. You can click on the used test case there on the left with the wrong answer. And Press the run button now. And now you should be able to see if it works for that test case. No, I don't. It's the same code, but I just can't figure out why it doesn't work. Let me try to really delve into why preson, because I'm thinking of a different strategy in mind. But but I just want to understand why this code isn't working. Less profit profit just one for into I size. If min is greater than price is I than you keep going down. Otherwise last profit equals profit. So you say the last profit equals the current profit and you say current profit is profis I minus min. So the last minimum. So you're trying to find the last minimum with a new maximum. And if last profit is greater than profit, well, you should really just add. Profit plus equals last profit. This should always be positive anyway. It should never be negative, right? Because you will, you already checthat. There must be. So you must say profit plus equals less profits. Hope this goes wrong. It should be equals because it I mean, my thought process was that it it was bigger than it would reset. Would fall back to the last value. I see. Okay. But think about it this way, right? If you go back to the description of the problem, they're on the left up near wrong. Answer a bit more description. It says you want to maximize your profit by choosing a single day to buy one stock and choosing a different day in the future to sell that stock. Return the maximum profit you can achieve from this transaction. If you cannot achieve any profit, return zero. So you want to find the biggest difference between min and max. What you could do. So you're you're basically doing this already. But what you can do is you can say if you if you have this graph, for example, here you go through it and here you've already got it right? Min is less is greater to them. Press ses. I so min is precise. So you're going down. We reach a maximum. We start going up. If we get too high, if we start going down again, we store that into a variable called max profit. And we start going down again, and we get this new minmum, new maximum, and then we say, Oh, this difference diff. Is it bigger than max profit? And if it is, than max profit? So that's kind of what you did over here. Yeah. But I think mine doesn't need that new calculation, just goes here down. It calculates every profit here until here the new minimum is reached. And then it starts going up here. It stores the new profit. And if it falls, it falls back to that profit. And as it goes up, it stores itself because it greater and then it goes to the top. And then once it falls because profit is less is it falls back to the last profit, which is here, which is the main one. Yeah but I'm wondering if that could fail somewhere in the future. Unsigned for int, I equals one, I equals a zero. No, no, because min is already set to zero. You're right. I equals one size. We say min equals Press ses. I. Profit equals price is I minus mbecause? We're kind of rolling that behind us. Profit that profit, it was profit. Proequals price is five us. Should I do that only if profit is greater than profit last profit is set. I feel like the problem with this line of code is that we're resetting every time. Yeah. So because if you're going back, so when you're going down, it's very it's very obvious that you're going down, right? You're going down and you're just saying min equals price is I and then you just keep going down. And then once you've set min price, you see profit equals price is I minus min, but you're resetting it every single time, right? You're basically saying every time you go up, that's your new that's your new difference. So instead of doing a new difference every single time, you want na find a way to add that up. You want to find a way to do nothing until you get to the maximum. And then once you get to the maximum, then you put profit equals Press min or max minus min and then that will be your total profit, right? Instead of this would be the same though as this. I'm not I'm not convinced because here what we do is we say last profit equals profit. So we take the last profit that we made and we say it's just equal to profit, which minus one at first I think I know why this failed. Okay. And that should work. Oh very nice. It's a TypeError. I didn't even realize. Wow. Okay, I'm actually kind of stumped. How did you fix that? I changed from char to short. No char max is 127 and so wereach 127 and just return that. Yeah, okay. I even spot then it falls back, then it overloads to the negative and then it's just gonna return that because last profit is always 127. That makes so much sense. I hadn't even realized that. Henry. Good job. Good, good job. We have we've ran out of time, but this is really fantastic to watch. Man, you've really improved and I think I think you're quite good at these problems. I mean, this is a great example of it. I didn't I wasn't even able to debug your code, right? So honestly, let's see if it works in the submissions. Nice. Yeah, very good. So honestly, hats off to you. You did some great work today. Great start of the year. And if you're still up for doing these kind of leak code problems, we can keep doing that if that's what you're interested in. I'm not sure what you think about that. Yeah, I think it's good. And Yeah your C++code are really is really good. I almost think that we should start start doing it in Python not only for you, but also for me so I can follow what's going on because my my C++, as you can tell, I didn't even realize there was a type issue. But but Yeah, great job as usual. And you know let's do something similar. Next lesson. Okay. Does it translate it? No, Yeah, unfortunately not. But I'm a lot more that that's Python. The difference between these two though, Yeah says Python two and Python three. Python two is old and we don't really use any more. Python three is typed as well now, but Yeah type ped c. You've got a list precishes, but it's like loosely typed. It's kind of interesting. But I'll be able to help you a lot more with Python because I actually know a lot of Python, whereas C++I coin it, but Yeah, I okay, great job. Great work and have a nice rest of your holiday. Thank you. Bye sir. You too. Bye bye.
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{
    "header_icon": "fas fa-crown",
    "course_title_en": "Language Course Summary",
    "course_title_cn": "语言课程总结",
    "course_subtitle_en": "1v1 CS Review Lesson",
    "course_subtitle_cn": "1v1 计算机科学复习课",
    "course_name_en": "0114 CS Henry",
    "course_name_cn": "0114 CS 亨利课",
    "course_topic_en": "Cyber Security Concepts and LeetCode Problem Solving (Best Time to Buy and Sell Stock)",
    "course_topic_cn": "网络安全概念回顾与LeetCode问题解决(买卖股票的最佳时机)",
    "course_date_en": "January 14",
    "course_date_cn": "1月14日",
    "student_name": "Henry",
    "teaching_focus_en": "Review of fundamental cybersecurity terms (Worm, Spyware, Phishing, DoS\/DDoS, IDE, IP\/TCP) and practicing advanced algorithm problem-solving in LeetCode.",
    "teaching_focus_cn": "复习基础网络安全术语(蠕虫、间谍软件、网络钓鱼、拒绝服务攻击、IDE、IP\/TCP)以及在LeetCode中练习高级算法问题解决。",
    "teaching_objectives": [
        {
            "en": "Student successfully recalls definitions for key cybersecurity concepts.",
            "cn": "学生能够成功回忆起关键网络安全概念的定义。"
        },
        {
            "en": "Student demonstrates iterative improvement in complex algorithmic thinking (LeetCode).",
            "cn": "学生在复杂算法思维(LeetCode)中表现出持续的改进。"
        },
        {
            "en": "Student correctly identifies primary\/secondary storage types and ordering based on speed.",
            "cn": "学生能正确识别主要\/次要存储类型并根据速度进行排序。"
        }
    ],
    "timeline_activities": [
        {
            "time": "0:00-10:00",
            "title_en": "Cybersecurity Terminology Review (Worm, Spyware, Phishing vs. Pharming, DoS\/DDoS)",
            "title_cn": "网络安全术语回顾(蠕虫、间谍软件、网络钓鱼 vs. 撞库攻击、DoS\/DDoS)",
            "description_en": "Reviewing definitions for terms like Worm, Spyware, Phishing\/Pharming distinction, and DoS\/DDoS attacks.",
            "description_cn": "回顾蠕虫、间谍软件、网络钓鱼\/撞库攻击的区别以及DoS\/DDoS攻击等术语的定义。"
        },
        {
            "time": "10:00-20:00",
            "title_en": "Review: IDE, IP Packets, TCP, and SSL\/TLS Handshake",
            "title_cn": "回顾:IDE、IP数据包、TCP和SSL\/TLS握手",
            "description_en": "Discussing the function and advantages\/disadvantages of IDEs, contents of an IP packet, TCP acknowledgement process, and the SSL certificate validation flow.",
            "description_cn": "讨论IDE的功能及优缺点、IP数据包的内容、TCP确认过程以及SSL证书验证流程。"
        },
        {
            "time": "20:00-30:00",
            "title_en": "Storage Hierarchy Review (Primary, Secondary, Tertiary) and Speed Ordering",
            "title_cn": "存储层级回顾(主存、次存、三级存储)与速度排序",
            "description_en": "Identifying storage types (RAM, ROM, HDD, SSD, USB, Cache, Register) and ordering them by speed (Register fastest). Detailed discussion on RAM vs. ROM and Heap location.",
            "description_cn": "识别存储类型(RAM、ROM、HDD、SSD、USB、缓存、寄存器)并按速度排序(寄存器最快)。详细讨论RAM与ROM的区别以及堆(Heap)的位置。"
        },
        {
            "time": "30:00-35:00",
            "title_en": "Review: CPU Bus Architecture and Bit-width",
            "title_cn": "回顾:CPU总线架构和位宽",
            "description_en": "Reviewing the three main buses (Data, Address, Control) and the relationship between CPU architecture bit-width (e.g., 64-bit) and bus width.",
            "description_cn": "回顾三种主要总线(数据、地址、控制)以及CPU架构位宽(如64位)与总线位宽之间的关系。"
        },
        {
            "time": "35:00-55:00",
            "title_en": "LeetCode Practice: Best Time to Buy and Sell Stock (Medium)",
            "title_cn": "LeetCode练习:《买卖股票的最佳时机》(中等难度)",
            "description_en": "Student attempts to solve the stock problem, debugging issues related to profit calculation and handling potential integer overflow (TypeError due to char size in intermediate steps).",
            "description_cn": "学生尝试解决股票问题,调试了与利润计算和潜在的整数溢出(中间步骤中char大小导致的TypeError)相关的错误。"
        },
        {
            "time": "55:00-60:00",
            "title_en": "Conclusion and Next Steps Discussion",
            "title_cn": "总结与后续步骤讨论",
            "description_en": "Teacher praises the significant improvement, especially in debugging the LeetCode solution, and suggests continuing with LeetCode problems, possibly transitioning to Python for coding exercises.",
            "description_cn": "老师称赞了学生显著的进步,尤其是在调试LeetCode解决方案方面,并建议继续进行LeetCode练习,可能将编程语言转换为Python。"
        }
    ],
    "vocabulary_en": "Malware, Propagates, Self-replicating, Spyware, Phishing, Pharming, Denial of Service (DoS), Distributed Denial of Service (DDoS), Integrated Development Environment (IDE), IP Packet, TCP, Acknowledge, Serial, Parallel, SSL (Secure Socket Layer), Certificate Authority (CA), Primary Storage, Secondary Storage, Tertiary Storage, RAM (Random Access Memory), ROM (Read-Only Memory), Heap, Cache, Register, Bus (Data, Address, Control), Accumulator, Program Counter (PC), ALU, Fetch-Decode-Execute cycle, Architecture, Bus Width, Byte.",
    "vocabulary_cn": "恶意软件, 传播, 自我复制, 间谍软件, 网络钓鱼, 撞库攻击\/伪造, 拒绝服务攻击, 分布式拒绝服务攻击, 集成开发环境, IP数据包, 传输控制协议, 确认, 串行, 并行, 安全套接字层, 证书颁发机构, 主存储器, 次级存储器, 三级存储器, 随机存取存储器, 只读存储器, 堆, 缓存, 寄存器, 总线(数据、地址、控制), 累加器, 程序计数器, 算术逻辑单元, 取指-译码-执行周期, 架构, 总线宽度, 字节。",
    "concepts_en": "Worm (self-replicating malware), Phishing vs. Pharming (general vs. targeted data theft), DoS vs. DDoS (overloading server), IDE features, IP\/TCP connection process, SSL certificate verification flow, Storage hierarchy differences (direct vs. indirect CPU access), RAM\/ROM distinction (volatility), Importance of matching CPU architecture bit-width to bus size, CPU internal components (CU, ALU, Registers, Buses).",
    "concepts_cn": "蠕虫(自我复制的恶意软件), 网络钓鱼 vs. 撞库攻击(泛指 vs. 针对性数据窃取), DoS vs. DDoS(服务器过载), IDE功能, IP\/TCP连接过程, SSL证书验证流程, 存储层级差异(CPU直接访问 vs. 间接访问), RAM\/ROM区别(易失性), CPU架构位宽与总线大小匹配的重要性, CPU内部组件(CU、ALU、寄存器、总线)。",
    "skills_practiced_en": "Verbal recall of technical definitions, Differentiation between similar concepts (Phishing\/Pharming), Analyzing complex security protocols (SSL), Categorization and ordering of hardware components by performance, Debugging algorithmic logic errors in a competitive programming context (C++).",
    "skills_practiced_cn": "技术定义的口头回忆, 区分相似概念(网络钓鱼\/撞库), 分析复杂安全协议(SSL), 按性能对硬件组件进行分类和排序, 在竞赛编程环境(C++)中调试算法逻辑错误。",
    "teaching_resources": [
        {
            "en": "Instructor's verbal prompts and definitions.",
            "cn": "教师的口头提示和定义。"
        },
        {
            "en": "LeetCode problem description (Best Time to Buy and Sell Stock, ID: 121).",
            "cn": "LeetCode问题描述(买卖股票的最佳时机,ID: 121)。"
        }
    ],
    "participation_assessment": [
        {
            "en": "High engagement throughout the review session, demonstrating willingness to attempt difficult recall questions.",
            "cn": "在整个复习过程中参与度高,表现出尝试回答困难回忆性问题的意愿。"
        },
        {
            "en": "Active participation during the LeetCode debugging session, driving the solution process.",
            "cn": "在LeetCode调试环节中积极参与,推动了解题过程。"
        }
    ],
    "comprehension_assessment": [
        {
            "en": "Strong grasp of basic cybersecurity definitions; struggled slightly with the nuance between Phishing and Pharming initially but corrected quickly.",
            "cn": "对基础网络安全定义掌握牢固;最初在网络钓鱼和撞库攻击的区别上略有挣扎,但很快得到纠正。"
        },
        {
            "en": "Excellent understanding of storage hierarchy, successfully identifying primary storage types and ordering speeds accurately.",
            "cn": "对存储层级有极好的理解,成功识别了主存储器类型并准确排序了速度。"
        }
    ],
    "oral_assessment": [
        {
            "en": "Answers are generally clear, though the student sometimes needs prompting to include all key components of a definition (e.g., self-replicating for Worm).",
            "cn": "回答通常清晰,尽管学生有时需要提示才能包含定义的所有关键部分(例如,蠕虫的“自我复制”)。"
        },
        {
            "en": "Excellent communication during the complex debugging process on LeetCode, articulating changes in strategy clearly.",
            "cn": "在复杂的LeetCode调试过程中沟通出色,清晰地阐述了策略的变化。"
        }
    ],
    "written_assessment_en": "The C++ code written during the LeetCode session showed correct implementation attempts but revealed a critical error related to variable type size (char vs. short\/int), leading to an unexpected overflow bug.",
    "written_assessment_cn": "在LeetCode环节中编写的C++代码显示了正确的实现尝试,但暴露了一个与变量类型大小(char vs. short\/int)相关的关键错误,导致了意外的溢出错误。",
    "student_strengths": [
        {
            "en": "Strong memory for recently reviewed complex topics, especially in CPU architecture and storage hierarchy.",
            "cn": "对近期复习的复杂主题记忆力强,特别是在CPU架构和存储层级方面。"
        },
        {
            "en": "Exceptional ability to debug and self-correct algorithmic logic, even under time pressure (LeetCode).",
            "cn": "在算法逻辑调试方面表现出卓越的能力,即使在时间压力下也能自我纠正(LeetCode)。"
        },
        {
            "en": "Accurately identified the integer overflow issue (TypeError) in C++ code that the instructor initially missed.",
            "cn": "准确识别了C++代码中连老师都差点忽略的整数溢出问题(TypeError)。"
        }
    ],
    "improvement_areas": [
        {
            "en": "Need to ensure fundamental definitions are consistently recalled (e.g., making sure to mention 'self-replicating' for a worm).",
            "cn": "需要确保基础定义的持续回忆(例如,提到蠕虫的“自我复制”)。"
        },
        {
            "en": "Requires careful attention to data types and potential overflows when coding, particularly in C++.",
            "cn": "编码时需要特别注意数据类型和潜在的溢出问题,尤其是在C++中。"
        }
    ],
    "teaching_effectiveness": [
        {
            "en": "The mixed format (theory review followed by practical coding) proved highly effective for engagement and assessment.",
            "cn": "混合模式(理论复习后接实际编码)在提高参与度和评估方面被证明非常有效。"
        },
        {
            "en": "The rapid-fire review session effectively tested retention across diverse CS topics.",
            "cn": "快速问答复习环节有效地检验了学生在各种计算机科学主题上的知识保留情况。"
        }
    ],
    "pace_management": [
        {
            "en": "The pace for the theory review was fast but appropriate, pushing the student to recall information quickly.",
            "cn": "理论复习的节奏很快但很恰当,促使学生快速回忆信息。"
        },
        {
            "en": "The final 25 minutes spent debugging LeetCode was intense but productive, showing the student's capacity for deep focus.",
            "cn": "最后25分钟用于调试LeetCode非常紧张但富有成效,显示了学生深度专注的能力。"
        }
    ],
    "classroom_atmosphere_en": "The atmosphere was encouraging, supportive, and intellectually challenging, especially during the debugging part where the student demonstrated great resilience.",
    "classroom_atmosphere_cn": "课堂氛围是鼓励、支持和智力挑战性的,尤其是在学生表现出极大韧性的调试环节中。",
    "objective_achievement": [
        {
            "en": "Objective 1 achieved with high success across multiple technical domains.",
            "cn": "目标1在多个技术领域取得了高成功率。"
        },
        {
            "en": "Objective 2 demonstrated significant achievement through the successful debugging process.",
            "cn": "目标2通过成功的调试过程得到了显著的实现。"
        },
        {
            "en": "Objective 3 fully achieved during the storage hierarchy review.",
            "cn": "目标3在存储层级回顾中得到完全实现。"
        }
    ],
    "teaching_strengths": {
        "identified_strengths": [
            {
                "en": "Effective scaffolding during LeetCode by focusing on the student's logic before addressing syntax\/type errors.",
                "cn": "在LeetCode中,通过关注学生的逻辑而非语法\/类型错误来进行有效的脚手架式指导。"
            },
            {
                "en": "Thorough review covering both high-level concepts (Security) and low-level implementation details (CPU\/Storage).",
                "cn": "复习内容全面,涵盖了高层概念(安全)和底层实现细节(CPU\/存储)。"
            }
        ],
        "effective_methods": [
            {
                "en": "Using 'fill-in-the-blank' or comparison questions (Phishing vs. Pharming, RAM vs. ROM) to force detailed recall.",
                "cn": "使用“填空”或比较问题(网络钓鱼 vs. 撞库攻击,RAM vs. ROM)来迫使详细回忆。"
            },
            {
                "en": "Allowing the student to drive the debugging process, providing minimal intervention until necessary.",
                "cn": "允许学生主导调试过程,仅在必要时提供最少的干预。"
            }
        ],
        "positive_feedback": [
            {
                "en": "Praise regarding the student's growth and confidence since previous sessions.",
                "cn": "对学生自上次课程以来的成长和自信心表示赞扬。"
            },
            {
                "en": "Acknowledging the student's superior debugging skill when spotting the C++ type issue.",
                "cn": "认可学生在发现C++类型问题时的卓越调试技能。"
            }
        ]
    },
    "specific_suggestions": [
        {
            "icon": "fas fa-microchip",
            "category_en": "Computer Architecture & Data Types",
            "category_cn": "计算机体系结构与数据类型",
            "suggestions": [
                {
                    "en": "Focus on the implications of language choice (C++ vs. Python) on memory management and type safety for future algorithm work.",
                    "cn": "在未来的算法工作中,关注编程语言选择(C++与Python)对内存管理和类型安全的影响。"
                },
                {
                    "en": "Revisit the exact memory structure of the CPU (MDR, MAR, PC, IR) to ensure the schematic drawing is complete next time.",
                    "cn": "重新回顾CPU的确切内存结构(MDR, MAR, PC, IR),确保下次绘图的完整性。"
                }
            ]
        },
        {
            "icon": "fas fa-lock",
            "category_en": "Cybersecurity Concepts",
            "category_cn": "网络安全概念",
            "suggestions": [
                {
                    "en": "Create brief flashcards to distinguish between similar concepts like Phishing\/Pharming and DoS\/DDoS attacker methods.",
                    "cn": "制作简短的闪卡来区分相似概念,如网络钓鱼\/撞库攻击和DoS\/DDoS攻击者方法。"
                }
            ]
        },
        {
            "icon": "fas fa-code",
            "category_en": "Algorithmic Practice",
            "category_cn": "算法练习",
            "suggestions": [
                {
                    "en": "Continue practicing Medium-level LeetCode problems, focusing on dynamic programming or array manipulation patterns.",
                    "cn": "继续练习中等难度的LeetCode问题,重点关注动态规划或数组操作模式。"
                }
            ]
        }
    ],
    "next_focus": [
        {
            "en": "Deep dive into CPU schematic drawing, including all registers (MDR, MAR, IR, PC) and bus connections.",
            "cn": "深入研究CPU示意图绘制,包括所有寄存器(MDR、MAR、IR、PC)和总线连接。"
        },
        {
            "en": "Transition coding exercises to Python for better instructor support and clearer type handling.",
            "cn": "将编程练习过渡到Python,以便获得更好的教师支持和更清晰的类型处理。"
        }
    ],
    "homework_resources": [
        {
            "en": "Review notes on the SSL Handshake process, focusing on the role of the Certificate Authority (CA).",
            "cn": "复习SSL握手过程的笔记,重点关注证书颁发机构(CA)的作用。"
        },
        {
            "en": "Attempt another Medium-level LeetCode problem related to arrays or strings.",
            "cn": "尝试另一个与数组或字符串相关的中等难度的LeetCode问题。"
        }
    ]
}
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